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The given function is f(x) =4x3 – 18x2 + 27x – 7 On differentiating both sides with respect to x, we getf (x) = 12x2-36x +27⇒ f (x) = 3(4x2-12x+9)⇒
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Find CBSE, ICSE State Boards Textbook Solutions of Class 8 to 12 of all subjects. Read NCERT Textbooks Questions and Answers & Find Previous year solved papers.
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Mrs Pumphrey was worried about Tricki because he would not eat anything. He refused to eat his favourite dishes and had bouts of vomiting. He spent all the time
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Given, po = 185 torr at 20oCps = 183 torr at 20oCMass of non-volatile substance,m= 1.2 gMass of acetone taken = 100 gAs we have,putting the values, we get
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Franz did not wish to go to school that morning because his teacher M. Hamel was to question them on ‘Participles’. He did not know a word about participle
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Assume, a point P from point charge q .Electrical potential, V=+50 Vdistance between the charge and point P=0.9 mWe have to find the magnitude of charge q.Pote
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प्रसंग- प्रस्तुत पद कृष्ण-भक्ति के प्रमुख कवि सूरदास के द्वारा रचित ‘सूरसागर’ में संकलित ‘भ्रमर गीत’ प्रसंग से लिया गया है। इसे हमारी पाठ्य-पुस्तक क्षितिज भाग- 2 में संकलित किया गया है। गोपियां सगुण-प्रेम-पथ के प्रति अपनी निष्ठा प्रकट करती हैं और मानती हैं कि वे किसी भी प्रकार स्वयं को श्रीकृष्ण के प्रेम से दूर नहीं कर सकतीं।

व्याख्या- गोपियां उद्धव की प्रेमहीनता पर व्यंग्य करती हुई कहती हैं कि हे उद्धव! तुम सचमुच बड़े भाग्यशाली हो क्योंकि तुम प्रेम के बंधन से पूरी तरह मुक्त हो, अनासक्त हो और तुम्हारा मन किंसी के प्रेम में डूबता नहीं। तुम श्रीकृष्ण के निकट रह कर भी उन के प्रेम बंधन से उसी त

Total increase in income = Increase in investment x K = 500 x 4 = 2,000 crores.Total increase in consumption expenditure = 0.75 of 2,000 = 1,500 crores.
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LHS= cos 38° . cos 52° - sin 38° . sin 52°= cos (90°-52°). cos 52°-sin (90° - 52°). sin 52°= sin 52° . cos 52° - cos 52° . sin 52°= 0 = RHS Prov
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यह कथन सर्वथा सही हैं की राज
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(i) Be2 molecule: The electronic configuration of Be(Z = 4) is:4 Be 1s2 2s1Be2 molecule is formed by the overlap of atomic orbitals of both beryllium atoms.
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(Get CBSE, ICSE and all State Boards textbook solutions for all subjects Class 8 to 12. You can also get CBSE solved papers of previous year from here! You can also prepare for SSC. Can also test SSC, find SSC Resource centre ! You can get resources online for free for NEET, NEET previous year solved paper and JEE, JEE Previous year solved papers! Student can also find the, previous year

जैन धर्म की मुख्य शिक्षाएँ इस प्रकार हैं: अहिंसा: जैन धर्म की शिक्षाओं का केंद्र-बिंदु अहिंसा का सिद्धांत है।(Find detailed answer | clicking on this link)

(Get CBSE, ICSE and all State Boards textbook solutions for all subjects Class 8 to 12. You can also get CBSE solved papers of previous year from here! You can also prepare for SSC. Can also test SSC, find SSC Resource centre ! You can get resources online for free for NEET, NEET previous year solved paper and JEE, JEE Previous year solved papers! Student can also find the, previous year papers etc. This is an organization related to th